Toggle Consonants Adjacent to Vowels

PKJ

 Coding Problem Keys 

 Toggle Consonants Adjacent to Vowels 

 Problem Statement 

The program must accept a string S containing only alphabets both in lower and upper case. The program must toggle the case of the consonants (non-vowels) adjacent to the vowels.

 Boundary Condition(s) 

2 <= Length of the string S <= 100

 Input Format 

The first line contains the string value S.

 Output Format 

The first line contains the toggle consonants between vowels.

 Example Input/Output 1 

 Input 

adJaeCent

 Output 

aDjaeceNt

 Example Input/Output 2 

 Input 

mAtRIMonY

 Output 

MATrImoNY

 Note: Max Execution Time Limit: 5000 millisecs 

 Solution 

 Programming Language: Python 3 Language 

s=input().strip()
vow="AEIOUaeiou"
for i in range(len(s)):
    if s[i] not in vow and ((i>0 and s[i-1] in vow) or (i+1<len(s) and s[i+1] in vow)):
        print(s[i].swapcase(),end="")
    else:
        print(s[i],end="")
# Published By PKJCODERS

 Alter 

def display(y):
    if y.islower():print(y.upper(),end='')
    else:print(y.lower(),end='')
s=""+input().strip()+"" 
n='aeiouAEIOU'
for i in range(len(s)):
    if s[i] not in n and ((i>0 and s[i-1] in n) or (i+1<len(s) and s[i+1] in n)):
        display(s[i]) 
    else:
        print(s[i],end='')
# Published By PKJCODERS

 Programming Language: C Language 

#include<stdio.h>
#include <stdlib.h>
int main(){
    int i,j,k,n;
    char s[100];
    scanf("%s",s);
    char x,l,m;
    n=strlen(s);
    for(i=0;i<n;i++){
        x=tolower(s[i]);
        l=tolower(s[i-1]);
        m=tolower(s[i+1]);
        if(x=='a'||x=='e'||x=='i'||x=='o'||x=='u')
            printf("%c",s[i]);
        else if((x!='a'&&x!='e'&&x!='i'&&x!='o'&&x!='u')&&(l=='a'||l=='e'||l=='i'||l=='o'||l=='u')||(m=='a'||m=='e'||m=='i'||m=='o'||m=='u'))
            if(isupper(s[i]))
                printf("%c",tolower(s[i]));
            else
                printf("%c",toupper(s[i]));
        else
            printf("%c",s[i]);
    }
}
//Published By PKJCODERS

 (Note: Incase If the code doesn't Pass the output kindly comment us with your feedback to help us improvise.) 

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