Equidistant Characters from Start & End

 Coding Problem Keys 

 Equidistant Characters from Start & End 

 Problem Statement 

Given a string value S1 the program must print only the character which are present in the same position from the start of S1 as well as the end of S1 in the order of their occurrence.

 Boundary Condition(s) 

1 <= Length of S1 <= 1000

 Input Format 

The first line contains S1.

 Output Format 

The first line contains the string value containing the characters which are present in the same position from the start of S1 as well as the end of S1.

 Example Input/Output 1 

 Input 

engine

 Output 

en

 Explanation 

The character 'en' is present in same position from start ' engine' as well as the end 'engine' for the string 'engine'.

 Example Input/Output 2 

 Input 

malayalam

 Output 

malay

 Explanation 

The characters 'malay' is present in same position from start ' malayalam' as well as the end 'malayalam' for the string 'malayalam'

 Max Execution Time Limit: 5000 millisecs 

 Solution 

 Programming Language: C Language 

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
    char str1[1001];
    int i,j;
    scanf("%s",str1);
    int len=strlen(str1);
    for(i=0,j=len-1;i<=len/2,j>=len/2;i++,j--){
        if(str1[i]==str1[j]){
            printf("%c",str1[i]);
        }
    }
}

// Published By PKJCODERS

 Alter 

#include<stdio.h>
#include<string.h>
int main(){
    char a[1000];
    int i,n,r;
    scanf("%s",a);
    n=strlen(a);
    r=n/2;
    if(n%2==1)
        r+=1;
    for(i=0;i<r;i++){
        if(a[i]==a[n-1-i])
            printf("%c",a[i]);
    }
}

// Published By PKJCODERS

 (Note: Incase If the code doesn't Pass the output kindly comment us with your feedback to help us improvise.)