Sort Rows by Prime, Even and Odd Count

PKJ

 Coding Problem Keys 

 Sort Rows by Prime, Even and Odd Count 

 Problem Statement 

An integer matrix of size R*C is given as input. The program must sort the rows based on the number of prime numbers in descending order. If two rows contain the same number of prime numbers then sort the rows based on the number of even numbers(also non-prime). If two rows contain the same number of prime numbers and the same number of even numbers then sort the rows based on the number of odd numbers (also non-prime). If two rows contain the same number of prime numbers, even numbers and odd numbers then sort the rows based on the sum of elements of each row in descending order.

 Boundary Condition(s) 

1 <= R, C <= 100

 Input Format 

The first line contains the value of R and C separated by space(s).
Next R lines contains C integers each separated by space(s).

 Output Format 

R lines containing C integers with the rows sorted based on given conditions.

 Example Input/Output 1 

 Input 

5 5
4 6 4 3 1
3 1 1 5 3
1 7 2 3 3
3 2 6 9 8
1 4 3 7 4

 Output 

1 7 2 3 3
3 1 1 5 3
3 2 6 9 8
1 4 3 7 4
4 6 4 3 1

 Example Input/Output 2 

 Input 

4 4
2 1 2 3
3 4 1 2
9 7 9 3
7 4 2 3

 Output 

7 4 2 3
2 1 2 3
3 4 1 2
9 7 9 3

 Max Execution Time Limit: 5000 millisecs 

 Solution 

 Programming Language: Python 3 Language 

import math
def prime(ab):
    f=0
    if(ab<2):
        return 0
    for i in range(2,int(math.sqrt(ab))+1):
        if(ab%i==0):
            f=1
            break
    if(f==0):
        return 1
    else:
        return 0
a,b=map(int,input().split())
c=[list(map(int,input().split())) for i in range(a)]
d=[]
iterator=0
for i in c:
    pcount=0
    ecount=0
    ocount=0
    for j in i:
        if(prime(j)==1):
            pcount+=1
        if(j%2!=0):
            ocount+=1
        if(j%2==0):
            ecount+=1
    d.append([pcount,ecount,ocount,sum(i),i])
    iterator+=1
d=sorted(d,reverse=True)
for i in d:
    print(*i[4])

# Published By PKJCODERS

 (Note: Incase If the code doesn't Pass the output kindly comment us with your feedback to help us improvise.) 

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