Number of Profitable Days

PKJ

 Coding Problem Keys 

 Number of Profitable Days 

 Problem Statement 

The e-commerce company "TodaysApparel" has a list of sales values of N days. Some days the company made a profit, represented as a positive sales value. Other days the company incurred a loss, represented as a negative sales value. The company wishes to know the number of profitable days in the list.

Write a algorithm to help the company know the number of profitable days in the list.

 Input Format 

The first line of input consists of an integer - numDays representing the number of days (N).
The second line of input consists of N space-separated integers - sales[0], sales[1] .............. sales[N-1] representing the sales values of N days respectively.

 Output Format 

Print an integer representing the number of days the company made a profit.

 Example Input/Output 1 

 Input 

7
23 -7 13 -34 56 43 -12

 Output 

4

 Explanation 

The number of positive sales values in the list is 4. Hence the output is 4.

 Example Input/Output 2 

 Input 

8
12 45 -78 22 16 2 14 -23

 Output 

6

 Solution 

 Programming Language: Python 3 Language 

n=int(input())
l=list(map(int,input().split()))
c=0
for i in l:
    if i>0:
        c+=1
print(c)

# Published By PKJCODERS

 Programming Language: C Language 

#include <stdio.h>
int main() {
    int N,c=0;
    scanf("%d",&N);
    int arr[N];
    for(int i=0;i<N;i++)
        scanf("%d",&arr[i]);
    for(int i=0;i<N;i++)
        if(arr[i]>0)
            c++;
    printf("%d",c);
}

// Published By PKJCODERS

 Programming Language: C++ Language 

#include <iostream>
using namespace std;
int main() {
    int N,c=0;
    cin>>N;
    int arr[N];
    for(int i=0;i<N;i++)
        cin>>arr[i];
    for(int i=0;i<N;i++)
        if(arr[i]>0)
            c++;
    cout<<c;
}

// Published By PKJCODERS

 (Note: Incase If the code doesn't Pass the output kindly comment us with your feedback to help us improvise.) 

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