Electrostatic

 Coding Problem Keys 

 Electrostatics 

 Problem Statement 

Doug is fond of change, every now and then he tries to do new things. This time, he caught up with a rod comprising of negative (N) and positive (P) charges. He is asked to calculate the maximum net electrostatic field possible in the region due to the rod.

Note: Assume, Electrostatic Field = Total Charge * 100.

 Input Specification 

Input1: integer array denoting the magnitude of each charge

Input2: String denoting the nature of each charge, i-th entry represents a sign of charge at the i-th loccation in input1.

Input3: No. of charges it holds (Length of input1).

 Output Specification 

Return the maximum electrostatic field possible in the rod.

 Example Input/Output 1 

 Input 

Input1: {4,3,5}

Input2: PNP

Input3: 3

 Output 

Output: 600

 Explanation 

The maximum electric charge on the rod is 4 - 3 + 5 = 6 units, so the magnitude of the electric field would be 6 * 100 = 600.

 Example Input/Output 2 

 Input 

Input1: {2,3}

Input2: PN

Input3: 2

 Output 

Output: 100

 Explanation 

The maximum electric charge on the rod is 2 - 3 = 1 unit, so the magnitude of the electric field would be 1 * 100 = 100.

 Solution 

 Programming Language: JAVA Language 

import java.util.*;
public class Main {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        String str = sc.nextLine();
        String s = sc.nextLine();
        int n = sc.nextInt();
        int charge[] = new int[n];
        int count = 0;
        for(int i=0;i<str.length();i++){
            if(str.charAt(i)!=' '){
                charge[count] = str.charAt(i)-48;
                count++;
            }
        }
        int sum = 0;
        for(int i=0;i<n;i++){
            if(s.charAt(i)=='P')
                sum+=charge[i];
            else
                sum-=charge[i];
        }
        if(sum>0){
            System.out.print(sum*100);
        }else{
            System.out.print(-sum*100);
        }
    }
}

// Published By PKJCODERS

 Programming Language: Python 3 Language 

def electrostatic(a,b,n):
    for i in range(n):
        if(b[i])=='N':
            a[i]=a[i]*-1
    return abs(sum(a))*100
a=list(map(int,input().split()))
b=list(input().strip())
n=int(input())
print(electrostatic(a,b,n))

# Published By PKJCODERS

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